Optimal. Leaf size=337 \[ \frac{3 i \sin ^{-1}(a x)^2 \text{PolyLog}\left (2,-i e^{i \sin ^{-1}(a x)}\right )}{2 a c^2}-\frac{3 i \sin ^{-1}(a x)^2 \text{PolyLog}\left (2,i e^{i \sin ^{-1}(a x)}\right )}{2 a c^2}-\frac{3 \sin ^{-1}(a x) \text{PolyLog}\left (3,-i e^{i \sin ^{-1}(a x)}\right )}{a c^2}+\frac{3 \sin ^{-1}(a x) \text{PolyLog}\left (3,i e^{i \sin ^{-1}(a x)}\right )}{a c^2}+\frac{3 i \text{PolyLog}\left (2,-i e^{i \sin ^{-1}(a x)}\right )}{a c^2}-\frac{3 i \text{PolyLog}\left (2,i e^{i \sin ^{-1}(a x)}\right )}{a c^2}-\frac{3 i \text{PolyLog}\left (4,-i e^{i \sin ^{-1}(a x)}\right )}{a c^2}+\frac{3 i \text{PolyLog}\left (4,i e^{i \sin ^{-1}(a x)}\right )}{a c^2}+\frac{x \sin ^{-1}(a x)^3}{2 c^2 \left (1-a^2 x^2\right )}-\frac{3 \sin ^{-1}(a x)^2}{2 a c^2 \sqrt{1-a^2 x^2}}-\frac{i \sin ^{-1}(a x)^3 \tan ^{-1}\left (e^{i \sin ^{-1}(a x)}\right )}{a c^2}-\frac{6 i \sin ^{-1}(a x) \tan ^{-1}\left (e^{i \sin ^{-1}(a x)}\right )}{a c^2} \]
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Rubi [A] time = 0.296223, antiderivative size = 337, normalized size of antiderivative = 1., number of steps used = 18, number of rules used = 10, integrand size = 20, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.5, Rules used = {4655, 4657, 4181, 2531, 6609, 2282, 6589, 4677, 2279, 2391} \[ \frac{3 i \sin ^{-1}(a x)^2 \text{PolyLog}\left (2,-i e^{i \sin ^{-1}(a x)}\right )}{2 a c^2}-\frac{3 i \sin ^{-1}(a x)^2 \text{PolyLog}\left (2,i e^{i \sin ^{-1}(a x)}\right )}{2 a c^2}-\frac{3 \sin ^{-1}(a x) \text{PolyLog}\left (3,-i e^{i \sin ^{-1}(a x)}\right )}{a c^2}+\frac{3 \sin ^{-1}(a x) \text{PolyLog}\left (3,i e^{i \sin ^{-1}(a x)}\right )}{a c^2}+\frac{3 i \text{PolyLog}\left (2,-i e^{i \sin ^{-1}(a x)}\right )}{a c^2}-\frac{3 i \text{PolyLog}\left (2,i e^{i \sin ^{-1}(a x)}\right )}{a c^2}-\frac{3 i \text{PolyLog}\left (4,-i e^{i \sin ^{-1}(a x)}\right )}{a c^2}+\frac{3 i \text{PolyLog}\left (4,i e^{i \sin ^{-1}(a x)}\right )}{a c^2}+\frac{x \sin ^{-1}(a x)^3}{2 c^2 \left (1-a^2 x^2\right )}-\frac{3 \sin ^{-1}(a x)^2}{2 a c^2 \sqrt{1-a^2 x^2}}-\frac{i \sin ^{-1}(a x)^3 \tan ^{-1}\left (e^{i \sin ^{-1}(a x)}\right )}{a c^2}-\frac{6 i \sin ^{-1}(a x) \tan ^{-1}\left (e^{i \sin ^{-1}(a x)}\right )}{a c^2} \]
Antiderivative was successfully verified.
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Rule 4655
Rule 4657
Rule 4181
Rule 2531
Rule 6609
Rule 2282
Rule 6589
Rule 4677
Rule 2279
Rule 2391
Rubi steps
\begin{align*} \int \frac{\sin ^{-1}(a x)^3}{\left (c-a^2 c x^2\right )^2} \, dx &=\frac{x \sin ^{-1}(a x)^3}{2 c^2 \left (1-a^2 x^2\right )}-\frac{(3 a) \int \frac{x \sin ^{-1}(a x)^2}{\left (1-a^2 x^2\right )^{3/2}} \, dx}{2 c^2}+\frac{\int \frac{\sin ^{-1}(a x)^3}{c-a^2 c x^2} \, dx}{2 c}\\ &=-\frac{3 \sin ^{-1}(a x)^2}{2 a c^2 \sqrt{1-a^2 x^2}}+\frac{x \sin ^{-1}(a x)^3}{2 c^2 \left (1-a^2 x^2\right )}+\frac{3 \int \frac{\sin ^{-1}(a x)}{1-a^2 x^2} \, dx}{c^2}+\frac{\operatorname{Subst}\left (\int x^3 \sec (x) \, dx,x,\sin ^{-1}(a x)\right )}{2 a c^2}\\ &=-\frac{3 \sin ^{-1}(a x)^2}{2 a c^2 \sqrt{1-a^2 x^2}}+\frac{x \sin ^{-1}(a x)^3}{2 c^2 \left (1-a^2 x^2\right )}-\frac{i \sin ^{-1}(a x)^3 \tan ^{-1}\left (e^{i \sin ^{-1}(a x)}\right )}{a c^2}-\frac{3 \operatorname{Subst}\left (\int x^2 \log \left (1-i e^{i x}\right ) \, dx,x,\sin ^{-1}(a x)\right )}{2 a c^2}+\frac{3 \operatorname{Subst}\left (\int x^2 \log \left (1+i e^{i x}\right ) \, dx,x,\sin ^{-1}(a x)\right )}{2 a c^2}+\frac{3 \operatorname{Subst}\left (\int x \sec (x) \, dx,x,\sin ^{-1}(a x)\right )}{a c^2}\\ &=-\frac{3 \sin ^{-1}(a x)^2}{2 a c^2 \sqrt{1-a^2 x^2}}+\frac{x \sin ^{-1}(a x)^3}{2 c^2 \left (1-a^2 x^2\right )}-\frac{6 i \sin ^{-1}(a x) \tan ^{-1}\left (e^{i \sin ^{-1}(a x)}\right )}{a c^2}-\frac{i \sin ^{-1}(a x)^3 \tan ^{-1}\left (e^{i \sin ^{-1}(a x)}\right )}{a c^2}+\frac{3 i \sin ^{-1}(a x)^2 \text{Li}_2\left (-i e^{i \sin ^{-1}(a x)}\right )}{2 a c^2}-\frac{3 i \sin ^{-1}(a x)^2 \text{Li}_2\left (i e^{i \sin ^{-1}(a x)}\right )}{2 a c^2}-\frac{(3 i) \operatorname{Subst}\left (\int x \text{Li}_2\left (-i e^{i x}\right ) \, dx,x,\sin ^{-1}(a x)\right )}{a c^2}+\frac{(3 i) \operatorname{Subst}\left (\int x \text{Li}_2\left (i e^{i x}\right ) \, dx,x,\sin ^{-1}(a x)\right )}{a c^2}-\frac{3 \operatorname{Subst}\left (\int \log \left (1-i e^{i x}\right ) \, dx,x,\sin ^{-1}(a x)\right )}{a c^2}+\frac{3 \operatorname{Subst}\left (\int \log \left (1+i e^{i x}\right ) \, dx,x,\sin ^{-1}(a x)\right )}{a c^2}\\ &=-\frac{3 \sin ^{-1}(a x)^2}{2 a c^2 \sqrt{1-a^2 x^2}}+\frac{x \sin ^{-1}(a x)^3}{2 c^2 \left (1-a^2 x^2\right )}-\frac{6 i \sin ^{-1}(a x) \tan ^{-1}\left (e^{i \sin ^{-1}(a x)}\right )}{a c^2}-\frac{i \sin ^{-1}(a x)^3 \tan ^{-1}\left (e^{i \sin ^{-1}(a x)}\right )}{a c^2}+\frac{3 i \sin ^{-1}(a x)^2 \text{Li}_2\left (-i e^{i \sin ^{-1}(a x)}\right )}{2 a c^2}-\frac{3 i \sin ^{-1}(a x)^2 \text{Li}_2\left (i e^{i \sin ^{-1}(a x)}\right )}{2 a c^2}-\frac{3 \sin ^{-1}(a x) \text{Li}_3\left (-i e^{i \sin ^{-1}(a x)}\right )}{a c^2}+\frac{3 \sin ^{-1}(a x) \text{Li}_3\left (i e^{i \sin ^{-1}(a x)}\right )}{a c^2}+\frac{(3 i) \operatorname{Subst}\left (\int \frac{\log (1-i x)}{x} \, dx,x,e^{i \sin ^{-1}(a x)}\right )}{a c^2}-\frac{(3 i) \operatorname{Subst}\left (\int \frac{\log (1+i x)}{x} \, dx,x,e^{i \sin ^{-1}(a x)}\right )}{a c^2}+\frac{3 \operatorname{Subst}\left (\int \text{Li}_3\left (-i e^{i x}\right ) \, dx,x,\sin ^{-1}(a x)\right )}{a c^2}-\frac{3 \operatorname{Subst}\left (\int \text{Li}_3\left (i e^{i x}\right ) \, dx,x,\sin ^{-1}(a x)\right )}{a c^2}\\ &=-\frac{3 \sin ^{-1}(a x)^2}{2 a c^2 \sqrt{1-a^2 x^2}}+\frac{x \sin ^{-1}(a x)^3}{2 c^2 \left (1-a^2 x^2\right )}-\frac{6 i \sin ^{-1}(a x) \tan ^{-1}\left (e^{i \sin ^{-1}(a x)}\right )}{a c^2}-\frac{i \sin ^{-1}(a x)^3 \tan ^{-1}\left (e^{i \sin ^{-1}(a x)}\right )}{a c^2}+\frac{3 i \text{Li}_2\left (-i e^{i \sin ^{-1}(a x)}\right )}{a c^2}+\frac{3 i \sin ^{-1}(a x)^2 \text{Li}_2\left (-i e^{i \sin ^{-1}(a x)}\right )}{2 a c^2}-\frac{3 i \text{Li}_2\left (i e^{i \sin ^{-1}(a x)}\right )}{a c^2}-\frac{3 i \sin ^{-1}(a x)^2 \text{Li}_2\left (i e^{i \sin ^{-1}(a x)}\right )}{2 a c^2}-\frac{3 \sin ^{-1}(a x) \text{Li}_3\left (-i e^{i \sin ^{-1}(a x)}\right )}{a c^2}+\frac{3 \sin ^{-1}(a x) \text{Li}_3\left (i e^{i \sin ^{-1}(a x)}\right )}{a c^2}-\frac{(3 i) \operatorname{Subst}\left (\int \frac{\text{Li}_3(-i x)}{x} \, dx,x,e^{i \sin ^{-1}(a x)}\right )}{a c^2}+\frac{(3 i) \operatorname{Subst}\left (\int \frac{\text{Li}_3(i x)}{x} \, dx,x,e^{i \sin ^{-1}(a x)}\right )}{a c^2}\\ &=-\frac{3 \sin ^{-1}(a x)^2}{2 a c^2 \sqrt{1-a^2 x^2}}+\frac{x \sin ^{-1}(a x)^3}{2 c^2 \left (1-a^2 x^2\right )}-\frac{6 i \sin ^{-1}(a x) \tan ^{-1}\left (e^{i \sin ^{-1}(a x)}\right )}{a c^2}-\frac{i \sin ^{-1}(a x)^3 \tan ^{-1}\left (e^{i \sin ^{-1}(a x)}\right )}{a c^2}+\frac{3 i \text{Li}_2\left (-i e^{i \sin ^{-1}(a x)}\right )}{a c^2}+\frac{3 i \sin ^{-1}(a x)^2 \text{Li}_2\left (-i e^{i \sin ^{-1}(a x)}\right )}{2 a c^2}-\frac{3 i \text{Li}_2\left (i e^{i \sin ^{-1}(a x)}\right )}{a c^2}-\frac{3 i \sin ^{-1}(a x)^2 \text{Li}_2\left (i e^{i \sin ^{-1}(a x)}\right )}{2 a c^2}-\frac{3 \sin ^{-1}(a x) \text{Li}_3\left (-i e^{i \sin ^{-1}(a x)}\right )}{a c^2}+\frac{3 \sin ^{-1}(a x) \text{Li}_3\left (i e^{i \sin ^{-1}(a x)}\right )}{a c^2}-\frac{3 i \text{Li}_4\left (-i e^{i \sin ^{-1}(a x)}\right )}{a c^2}+\frac{3 i \text{Li}_4\left (i e^{i \sin ^{-1}(a x)}\right )}{a c^2}\\ \end{align*}
Mathematica [A] time = 0.403695, size = 234, normalized size = 0.69 \[ \frac{-6 \sin ^{-1}(a x) \text{PolyLog}\left (3,-i e^{i \sin ^{-1}(a x)}\right )+6 \sin ^{-1}(a x) \text{PolyLog}\left (3,i e^{i \sin ^{-1}(a x)}\right )+3 i \left (\sin ^{-1}(a x)^2+2\right ) \text{PolyLog}\left (2,-i e^{i \sin ^{-1}(a x)}\right )-3 i \left (\sin ^{-1}(a x)^2+2\right ) \text{PolyLog}\left (2,i e^{i \sin ^{-1}(a x)}\right )-6 i \text{PolyLog}\left (4,-i e^{i \sin ^{-1}(a x)}\right )+6 i \text{PolyLog}\left (4,i e^{i \sin ^{-1}(a x)}\right )+\frac{a x \sin ^{-1}(a x)^3}{1-a^2 x^2}-\frac{3 \sin ^{-1}(a x)^2}{\sqrt{1-a^2 x^2}}-2 i \sin ^{-1}(a x)^3 \tan ^{-1}\left (e^{i \sin ^{-1}(a x)}\right )-12 i \sin ^{-1}(a x) \tan ^{-1}\left (e^{i \sin ^{-1}(a x)}\right )}{2 a c^2} \]
Antiderivative was successfully verified.
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Maple [A] time = 0.149, size = 486, normalized size = 1.4 \begin{align*} -{\frac{x \left ( \arcsin \left ( ax \right ) \right ) ^{3}}{ \left ( 2\,{a}^{2}{x}^{2}-2 \right ){c}^{2}}}+{\frac{3\, \left ( \arcsin \left ( ax \right ) \right ) ^{2}}{2\,a \left ({a}^{2}{x}^{2}-1 \right ){c}^{2}}\sqrt{-{a}^{2}{x}^{2}+1}}-{\frac{ \left ( \arcsin \left ( ax \right ) \right ) ^{3}}{2\,a{c}^{2}}\ln \left ( 1+i \left ( iax+\sqrt{-{a}^{2}{x}^{2}+1} \right ) \right ) }+{\frac{{\frac{3\,i}{2}} \left ( \arcsin \left ( ax \right ) \right ) ^{2}}{a{c}^{2}}{\it polylog} \left ( 2,-i \left ( iax+\sqrt{-{a}^{2}{x}^{2}+1} \right ) \right ) }-3\,{\frac{\arcsin \left ( ax \right ){\it polylog} \left ( 3,-i \left ( iax+\sqrt{-{a}^{2}{x}^{2}+1} \right ) \right ) }{a{c}^{2}}}-{\frac{3\,i}{a{c}^{2}}{\it polylog} \left ( 4,-i \left ( iax+\sqrt{-{a}^{2}{x}^{2}+1} \right ) \right ) }+{\frac{ \left ( \arcsin \left ( ax \right ) \right ) ^{3}}{2\,a{c}^{2}}\ln \left ( 1-i \left ( iax+\sqrt{-{a}^{2}{x}^{2}+1} \right ) \right ) }-{\frac{{\frac{3\,i}{2}} \left ( \arcsin \left ( ax \right ) \right ) ^{2}}{a{c}^{2}}{\it polylog} \left ( 2,i \left ( iax+\sqrt{-{a}^{2}{x}^{2}+1} \right ) \right ) }+3\,{\frac{\arcsin \left ( ax \right ){\it polylog} \left ( 3,i \left ( iax+\sqrt{-{a}^{2}{x}^{2}+1} \right ) \right ) }{a{c}^{2}}}+{\frac{3\,i}{a{c}^{2}}{\it polylog} \left ( 4,i \left ( iax+\sqrt{-{a}^{2}{x}^{2}+1} \right ) \right ) }-3\,{\frac{\arcsin \left ( ax \right ) \ln \left ( 1+i \left ( iax+\sqrt{-{a}^{2}{x}^{2}+1} \right ) \right ) }{a{c}^{2}}}+3\,{\frac{\arcsin \left ( ax \right ) \ln \left ( 1-i \left ( iax+\sqrt{-{a}^{2}{x}^{2}+1} \right ) \right ) }{a{c}^{2}}}+{\frac{3\,i}{a{c}^{2}}{\it dilog} \left ( 1+i \left ( iax+\sqrt{-{a}^{2}{x}^{2}+1} \right ) \right ) }-{\frac{3\,i}{a{c}^{2}}{\it dilog} \left ( 1-i \left ( iax+\sqrt{-{a}^{2}{x}^{2}+1} \right ) \right ) } \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [A] time = 2.65373, size = 77, normalized size = 0.23 \begin{align*} -\frac{1}{4} \,{\left (\frac{2 \, x}{a^{2} c^{2} x^{2} - c^{2}} - \frac{\log \left (a x + 1\right )}{a c^{2}} + \frac{\log \left (a x - 1\right )}{a c^{2}}\right )} \arcsin \left (a x\right )^{3} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [F] time = 0., size = 0, normalized size = 0. \begin{align*}{\rm integral}\left (\frac{\arcsin \left (a x\right )^{3}}{a^{4} c^{2} x^{4} - 2 \, a^{2} c^{2} x^{2} + c^{2}}, x\right ) \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [F] time = 0., size = 0, normalized size = 0. \begin{align*} \frac{\int \frac{\operatorname{asin}^{3}{\left (a x \right )}}{a^{4} x^{4} - 2 a^{2} x^{2} + 1}\, dx}{c^{2}} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [F] time = 0., size = 0, normalized size = 0. \begin{align*} \int \frac{\arcsin \left (a x\right )^{3}}{{\left (a^{2} c x^{2} - c\right )}^{2}}\,{d x} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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